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Elementary Differential Equations and Boundary Value Problems - Boyce W.E.

Boyce W.E. Elementary Differential Equations and Boundary Value Problems - John Wiley & Sons, 2001. - 1310 p.
Download (direct link): elementarydifferentialequations2001.pdf
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To prove this statement, substitute Yt(t) + Y2(t) for in Eq. (18) and make use
of Eqs. (16) and (17). A similar conclusion holds if g(t) is the sum of any finite
number of terms. The practical significance of this result is that for an equation whose nonhomogeneous function g( t) can be expressed as a sum, one can consider instead several simpler equations and then add the results together. The following example is an illustration of this procedure.
Find a particular solution of
3 4 = 3e2t + 2sin t 8* cos 2t. (19)
By splitting up the right side ofEq. (19), we obtain the three equations
/- 3/ 4 = 3e2t,
' 3 4y = 2 sin t,
and
3/ 4y = 8* cos2t.
174
Chapter 3. Second Order Linear Equations
I
EXAMPLE
5
Solutions of these three equations have been found in Examples 1,2, and 3, respectively. Therefore a particular solution of Eq. (19) is their sum, namely,
Y(t) = 2e2t + (7 cos t (7 sin t + (0e1 cos 2t + e1 sin2t.
The procedure illustrated in these examples enables us to solve a fairly large class of problems in a reasonably efficient manner. However, there is one difficulty that sometimes occurs. The next example illustrates how it arises.
Find a particular solution of
' + 4 = 3 cos 2t. (20)
Proceeding as in Example 2, we assume that Y (t) = A cos 2t + B sin 2t .By substituting in Eq. (20), we then obtain
(4 A - 4 A) cos 2t + (4B - 4B) sin2t = 3 cos 2t. (21)
Since the left side of Eq. (21) is zero, there is no choice of A and B that satisfies this equation. Therefore, there is no particular solution ofEq. (20) of the assumed form. The reason for this possibly unexpected result becomes clear if we solve the homogeneous equation
/ + 4 = 0 (22)
that corresponds to Eq. (20). A fundamental set of solutions of Eq. (22) is yt(t) = cos2t and y2(t) = sin2t. Thus our assumed particular solution ofEq. (20) is actually a solution of the homogeneous equation (22); consequently, it cannot possibly be a solution of the nonhomogeneous equation (20).
To find a solution of Eq. (20) we must therefore consider functions of a somewhat different form. The simplest functions, other than cos2t and sin2t themselves, that when differentiated lead to cos 2t and sin 2t are t cos 2t and t sin 2t. Hence we assume that Y (t) = At cos2t + Bt sin 21. Then, upon calculating Y'(t) and Y"(t), substituting them into Eq. (20), and collecting terms, we find that
4 A sin2t + 4Bcos2t = 3cos2t.
Therefore A = 0 and B = 3/4, so a particular solution ofEq. (20) is
Y (t) = 41 sin2t.
The fact that in some circumstances a purely oscillatory forcing term leads to a solution that includes a linear factor t as well as an oscillatory factor is important in some applications; see Section 3.9 for a further discussion.
The outcome of Example 5 suggests a modification of the principle stated previously: If the assumed form of the particular solution duplicates a solution of the corresponding homogeneous equation, then modify the assumed particular solution by multiplying it by t. Occasionally, this modification will be insufficient to remove all duplication with the solutions of the homogeneous equation, in which case it is necessary to multiply
3.6 Nonhomogeneous Equations; Method of Undetermined Coefficients
175
by t a second time. For a second order equation, it will never be necessary to carry the process further than this.
Summary. We now summarize the steps involved in finding the solution of an initial value problem consisting of a nonhomogeneous equation of the form
af + by + cy = g(t), (23)
where the coefficients a, b, and c are constants, together with a given set of initial conditions:
1. Find the general solution of the corresponding homogeneous equation.
2. Make sure that the function g(t) in Eq. (23) belongs to the class of functions discussed in this section, that is, it involves nothing more than exponential functions, sines, cosines, polynomials, or sums or products of such functions. If this is not the case, use the method of variation of parameters (discussed in the next section).
3. If g(t) = gx(t) + + gn(t), that is, if g(t) is a sum of n terms, then form n
subproblems, each of which contains only one of the terms gl(t),..., gn (t). The th subproblem consists of the equation
ay" + by + cy = gi (t),
where runs from 1 to n.
4. For the th subproblem assume a particular solution Y (t) consisting of the appropriate exponential function, sine, cosine, polynomial, or combination thereof. If there is any duplication in the assumed form of Y (t) with the solutions of the homogeneous equation (found in step 1), then multiply Y (t) by t, or (if necessary) by t2, so as to remove the duplication. See Table 3.6.1.
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