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# Elementary Differential Equations and Boundary Value Problems - Boyce W.E.

Boyce W.E. Elementary Differential Equations and Boundary Value Problems - John Wiley & Sons, 2001. - 1310 p.
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Similarly, corresponding to the eigenvalue r2 = —4, we have f1 = -ë/2 ?2, so the eigenvector is
g(2) = (-/^) • (19)
Thus a fundamental set of solutions of the system (14) is
õà)(ë - ( e- x(2)(t) - (-'T2\ e-4t
x (t) = [V^) , (t) = I 1 ) e~ ’ (20)
and the general solution is
x = C1x(1)(t) + C2x(2) = e-t + c2 ^-1^^ e-4t• (21)
Graphs of the solution (21) for several values of c1 and c2 are shown in Figure
7.5.4a. The solution x(1)(t) approaches the origin along the line x2 = V2 x1, while the solution x(2)(t) approaches the origin along the line x1 = -ë/2 x2. The directions of
378
Chapter 7. Systems of First Order Linear Equations
these lines are determined by the eigenvectors ?(1) and ?(2), respectively. In general, we have a combination of these two fundamental solutions. As t ^ro, the solution x(2) (t) is negligible compared to x(1)(t). Thus, unless c1 = 0, the solution (21) approaches the origin tangent to the line x2 = \f2xr The pattern of trajectories shown in Figure
7.5.4a is typical of all second order systems x; = Ax for which the eigenvalues are real, different, and of the same sign. The origin is called a node for such a system. If the eigenvalues were positive rather than negative, then the trajectories would be similar but traversed in the outward direction. Nodes are asymptotically stable if the eigenvalues are negative and unstable if the eigenvalues are positive.
Although Figure 7.5.4a was computer-generated, a qualitatively correct sketch of the trajectories can be drawn quickly by hand, based on a knowledge of the eigenvalues and eigenvectors.
Some typical plots of x1 versus t are shown in Figure 7.5.46. Observe that each of the graphs approaches the t-axis asymptotically as t increases, corresponding to a trajectory that approaches the origin in Figure 7.5.2a. The behavior of x2 as a function of t is similar.
FIGURE 7.5.4 (a) Trajectories of the system (14); the origin is a node. (b) Plots of xj versus
t for the system (14).
The two preceding examples illustrate the two main cases for 2 x 2 systems having eigenvalues that are real and different: Either the eigenvalues have opposite signs (Example 1) or the same sign (Example 2). The other possibility is that zero is an eigenvalue, but in this case it follows that det A = 0, which violates the assumption made at the beginning of this section.
Returning to the general system (1) we proceed as in the examples. To find solutions of the differential equation (1) we must find the eigenvalues and eigenvectors of A
7.5 Homogeneous Linear Systems with Constant Coefficients
379
EXAMPLE
3
from the associated algebraic system (4). The eigenvalues rv .. all be different) are roots of the nth degree polynomial equation
det (A - rI) = 0.
, r (which need not
(22)
The nature ofthe eigenvalues and the corresponding eigenvectors determines the nature of the general solution of the system (1). If we assume that A is a real-valued matrix, there are three possibilities for the eigenvalues of A:
1. All eigenvalues are real and different from each other.
2. Some eigenvalues occur in complex conjugate pairs.
3. Some eigenvalues are repeated.
If the eigenvalues are all real and different, as in the two preceding examples, then associated with each eigenvalue rt is a real eigenvector g(l) and the set of n eigenvectors g(1),..., g(n) is linearly independent. The corresponding solutions of the differential system (1) are
(1)
(t) = g (1)eV,
(n)
- g (n) ernt.
(t) = g
(23)
To show that these solutions form a fundamental set, we evaluate their Wronskian:
(1) r t
W [x1
(1)
, x(n)](t) =
% i1' er1t
(n) r t % 1 ’ e nl
= e(ri+¦¦¦+rn)t
%1
(1)
%1
(n)
%
(1)
% (n n
(n)
(24)
First, we observe that the exponential function is never zero. Next, since the eigenvectors g(1),..., g(n) are linearly independent, the determinant in the last term of Eq. (24) is nonzero. As a consequence, the Wronskian W[x(1),..., x(n)](t) is never zero; hence x(1),..., x(n) form a fundamental set of solutions. Thus the general solution of Eq. (1) is
x = c1g (1)er1t + ¦¦¦ + cn g (n)ernt. (25)
If A is real and symmetric (a special case of Hermitian matrices), recall from Section 7.3 that all the eigenvalues rv ..., rn must be real. Further, even if some of the eigenvalues are repeated, there is always a full set of n eigenvectors g(1),..., g(n) that are linearly independent (in fact, orthogonal). Hence the corresponding solutions of the differential system (1) given by Eq. (23) again form a fundamental set of solutions and the general solution is again given by Eq. (25). The following example illustrates this case.
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