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Elementary Differential Equations and Boundary Value Problems - Boyce W.E.

Boyce W.E. Elementary Differential Equations and Boundary Value Problems - John Wiley & Sons, 2001. - 1310 p.
Download (direct link): elementarydifferentialequations2001.pdf
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28. The method of reduction of order (Section 3.5) can also be used for the nonhomogeneous equation
provided one solution y of the corresponding homogeneous equation is known. Let y = v(t)y (t) and show that y satisfies Eq. (i) if v is a solution of
Equation (ii) is a first order linear equation for v'. Solving this equation, integrating the result, and then multiplying by y1 (t) lead to the general solution of Eq. (i).
In each of Problems 29 through 32 use the method outlined in Problem 28 to solve the given differential equation.
29. t2 f - 2ty + 2y = 41, t > 0; y (t) = t
30. t2 + 7ty + 5y = t, t > 0; y (t) = t-1
31. ty'- (1 + t)y + y = t2e2t, t > 0; yl(t) = 1 + t (see Problem 15)
32. (1 - t) + ty - y = 2(t - 1)2e-t, 0 < t < 1; yl{t) = (see Problem 16)
L [y] = (aD2 + bD + c) y = g(t), y(t0) = 0, y(t0) = 0,
where a, b, and are constants, has the form
(i)
+ p(t) + q (t)y = g(t),
(i)
yl(t)v" + [2 (t) + p(t) yl(t)]v' = g(t).
(ii)
186
Chapter 3. Second Order Linear Equations
3.8 Mechanical and Electrical Vibrations
One of the reasons that second order linear equations with constant coefficients are worth studying is that they serve as mathematical models of some important physical processes. Two important areas of application are in the fields of mechanical and electrical oscillations. For example, the motion of a mass on a vibrating spring, the torsional oscillations of a shaft with a flywheel, the flow of electric current in a simple series circuit, and many other physical problems are all described by the solution of an initial value problem of the form
ay" + by + cy = g(t), y(0) = y0, (0) = 0. (1)
This illustrates a fundamental relationship between mathematics and physics: Many physical problems may have the same mathematical model. Thus, once we know how to solve the initial value problem (1), it is only necessary to make appropriate interpretations of the constants a, b, and c, and the functions y and g, to obtain solutions of different physical problems.
We will study the motion of a mass on a spring in detail because an understanding of the behavior of this simple system is the first step in the investigation of more complex vibrating systems. Further, the principles involved are common to many problems. Consider a mass m hanging on the end of a vertical spring of original length l, as shown in Figure 3.8.1. The mass causes an elongation L of the spring in the downward (positive) direction. There are two forces acting at the point where the mass is attached to the spring; see Figure 3.8.2. The gravitational force, or weight of the mass, acts downward and has magnitude mg, where g is the acceleration due to gravity. There is also a force Fs, due to the spring, that acts upward. If we assume that the elongation L of the spring is small, the spring force is very nearly proportional to L; this is known
L
T
u
FIGURE 3.8.1 A spring-mass system.
Fs = -kL
0
w = mg
FIGURE 3.8.2 Force diagram for a spring-mass system.
3.8 Mechanical and Electrical Vibrations
187
as Hookes8 law. Thus we write Fs = kL, where the constant of proportionality k is called the spring constant, and the minus sign is due to the fact that the spring force
acts in the upward (negative) direction. Since the mass is in equilibrium, the two forces
balance each other, which means that
mg kL = 0. (2)
For a given weight w = mg, one can measure L and then use Eq. (2) to determine k. Note that k has the units of force/length.
In the corresponding dynamic problem we are interested in studying the motion of the mass when it is acted on by an external force or is initially displaced. Let u(t), measured positive downward, denote the displacement of the mass from its equilibrium position at time t; see Figure 3.8.1. Then u(t) is related to the forces acting on the mass through Newtons law of motion,
mu" (t) = f(t), (3)
where u" is the acceleration of the mass and f is the net force acting on the mass. Observe that both u and f are functions of time. In determining f there are four separate forces that must be considered:
1. The weight w = mg of the mass always acts downward.
2. The spring force Fs is assumed to be proportional to the total elongation L + u of the spring and always acts to restore the spring to its natural position. If L + u > 0, then the spring is extended, and the spring force is directed upward. In this case
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